What is the value of the remainder if 10x4 – 6x3 + 5x2 – x + 1 is divided by x – 3?
Accepted Solution
A:
Answer:Remainder is 691.Step-by-step explanation:Given function is [tex]10x^4-6x^3+5x^2-x+1[/tex].Now we need to find remainder if we divide given function [tex]10x^4-6x^3+5x^2-x+1[/tex] by (x-3)(x-3) means plug x=3 into [tex]10x^4-6x^3+5x^2-x+1[/tex] to find remainder. [tex]10x^4-6x^3+5x^2-x+1[/tex][tex]=10(3)^4-6(3)^3+5(3)^2-(3)+1[/tex][tex]=10(81)-6(27)+5(9)-(3)+1[/tex][tex]=810-162+45-3+1[/tex][tex]=856-162-3[/tex][tex]=856-165[/tex][tex]=691[/tex]Hence remainder is 691.